Question

What is the equation in standard form of the line which passes through (4, –2) and has a slope of –3?

Answer 1

you have to use the formula
(y-y1) = m(x-x1)
where (x1,y1) are given points

Answer 2

y+3x=10

Answer 3

y=mx+b , m=-3 , (4,-2)
-2=-3(4)+b
-2=-12+b
12-2=b
10=b
so the equation is y=-3x+10

Answer 4

Start with point slope form and your info.
y-(-2)=-3(x-4)...................simplify
y+2 = -3x+12...................put in slope intercept form. Solve for y.
y=-3x+10.........................move x term to other side.
3x+y=10..........................be sure there are no fractions in the problem.