Question

solve using the quadratic equation 2x^2-3x-4=0

Answer 1

theres a formula to get the roots. all you need to do is to use it.. (3+sqrt(41))/4

Answer 2

quadratic formula:
\[x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]

Answer 3

oh okay

Answer 4

what do i do after i do that

Answer 5

u have a=2, b=-3 and c=-4, substitude in there u will get two solution

Answer 6

can we go to twiddla so i can show you what i have and you can tell me if i am right

Answer 7

i have no idea how to write it on here

Answer 8

i had not yet used twiddla but let try it now

Answer 9

ok i will send you the link
http://www.twiddla.com/590504

Answer 10

i have what i got on the problem up whenever you want to read it

Answer 11

my internet was disconnected by someone thats y i was gone now show ur problem

Answer 12

ok i got 8/5n^3 for the problem is that right

Answer 13

wait i m solving rit now

Answer 14

ur question plz, that was removed from there

Answer 15

ur answer is correct

Answer 16

i checked

Answer 17

ok and was it right

Answer 18

yes what wrong

Answer 19

can u tell me how to use twiddla?

Answer 20

ok well i can show you better than tell you

Answer 21

thats nice, what is first step, 2nd and so on

Answer 22

find reciprocal of 2nd fraction--- step 1
multiply fractions ---step 2
simplify numerator and denominator--step 3
get answer ---step 4

Answer 23

i know this, i asked what is twiddla? not this

Answer 24

it is like a blackboard where you can work on problems and show people how to do it

Answer 25

for example u do so that i see

Answer 26

yes i write out the problem and you can see how i worked it out and got my answer and you can also draw on it to correct something

Answer 27

ok try ur quadratic equation a little

Answer 28

ok i will show you my steps on twiddla if you want to
http://www.twiddla.com/590546

Answer 29

do it i m watching the screen