Question

xy^-1, x=2, y=3

Answer 1

is it 6

Answer 2

no it is
\[2\times 3^{-1}=\frac{2}{3}\]

Answer 3

ok thx

Answer 4

if your question is \[(xy)^-1\]
then answer is 1/6

Answer 5

Two tricks to this question. The first is order of operations. Parenthesis is done before multiplication, so 3^-1 is done before 2*.
The second trick is negative exponents. With a negative exponent, change the base to its reciprocal and then make the exponent positive. So you get this:
x*y^-1 =
2* 3^-1 =
2* (1/3)^1 =
2*(1/3) =
2/3