Question

simplify bt reducing the radical 49√y^21z^14

Answer 1

are you there?

Answer 2

yes

Answer 3

since there are 21 factors of y and 14 factors of z under the radical...

you can take pairs of them out...

for example in this more simple version root(y^3) = yroot(y)

so you can take 10 y's out and 7 z's...

but one y is left inside so its...

(y^10z^7)root(y)

Answer 4

\[49\sqrt{y^21z^14} = 49y ^{10} z^7\sqrt{y}\]

Answer 5

the problem is \[\sqrt[49]{y ^{21}z ^{14}}\]