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Mathematics 25 Online
OpenStudy (anonymous):

simplify (2x^2 y^3)(4xy^-2)

OpenStudy (aroub):

8 x^3 y

OpenStudy (anonymous):

\[(2x^2y^3)(4x/y^2)\]

OpenStudy (anonymous):

so, \[8x^3y\]

OpenStudy (anonymous):

I would separate the factors, first 2*4, then x^2*x, then y^3*y^-2 and then multiply what you get for each section by each other

OpenStudy (anonymous):

pro is right

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