Question

how do you solve [6y-(7x-2)][6y+(7x-2)]

Answer 1

why do i square it?

Answer 2

You can treat it like a binomial difference of squares
(6y - a) (6y +a) where a = 7x-2

Answer 3

what about the other side?

Answer 4

I did wonder about "solve"...

Answer 5

no it says find the product...

Answer 6

nvm thats simplify...

Answer 7

but still, do i do the same thing on the other side?

Answer 8

what other side?

Answer 9

its [6y-(7x-2)][6y+(7x-2)]?

Answer 10

OK, so there is just that, no sides....

Answer 11

and you want to multiply them together...

Answer 12

i have to find the product, yes.

Answer 13

Yes, that's the same thing.

The first post from Ryan is a good answer.

Are u expected to expand it all the way out.....?

Answer 14

no i dont think so

Answer 15

Then I would go with Ryan's answer.

Answer 16

so just 6y-a 6y+a?

Answer 17

Hmm... he appears to have deleted his answer..

Answer 18

so what do i do?

Answer 19

It was (6y)^2 - (7x-2)^2 which u could write as

36y^2 - (7x-2)^2 if u wanted to.

Answer 20

oh , alright

Answer 21

r u sure u are not expected to expand it all out?

Answer 22

\[(a+b)(a-b) = a^{2} - b^{2}\]
a=6y
b = 7x-2

Answer 23

\[(a+b)(a-b)=a^2-b^2\] put
\[a=6y, b=7x-2\] get
\[(6y)^2-(72-2)^2\]

Answer 24

yes

Answer 25

Ok, u r done, then.

Answer 26

\[(6y)^2-(7x-2)^2\]

Answer 27

satallite where did 72 come from?

Answer 28

Typo

Answer 29

you can multiply out if you like. get
\[36y^2-(49x^2-28x+4)\]

Answer 30

oh

Answer 31

Now we are repeating......