Question

A die is rolled twice. Find each probability.
1) P(2 then 3)
=(1/6)*(1/6)=1/36 ?
2) P( two 4s)
= (1/6)*(1/6)=1/36
3) P(two of the same number)?

Answer 1

you are doing it right

Answer 2

how 3 ?

Answer 3

same as the other two, there is a 1 in 6 probability of getting any number on each roll

Answer 4

so you can get any number on the first roll, and the next roll has a 1 in 6 chance of being the same number

Answer 5

so the answer is 1/6

Answer 6

does this make sense?

Answer 7

1) and 2) = 1/36 ?

Answer 8

yes

Answer 9

3)=1/6?

Answer 10

number 3 is 1/6, yes

Answer 11

I don't get 1/6
rolled twice, 1/6 only one variable need 2 varibal becausre rolled twice

Answer 12

you do not need a formula for two of the same number. just count
(1,1),(2,2),(3,3),(4,4), (5,5),(6,6)

Answer 13

6 out of 36 possibilities

Answer 14

thank satellite, good explain

Answer 15

you can count for others as well. two fours
(4,4) only one way
two and then 3
(2,3) one way

Answer 16

for two dice it is good to check the formula, but you can always just count successes. only 36 possibilities so it is not hard to count

Answer 17

yes, not hard just confuing