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simplify (a^3/ab)/(a^5b/a^3b^2)
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\[\frac{a^3}{ab}\times \frac{a^3b^3}{a^5b}\] is a start
then add up exponents top and bottom, then cancel by subtracting the exponents
ok let me try that
ok
i had a typo. should have been \[\frac{a^3}{ab}\times \frac{a^3b^2}{a^5b}\]
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i just got b everything else cancels out
yes in fact if i hadn't made my typo you would have seen that everything cancels and you get 1
i put a b^3 in the numerator, should have been b^2
i saw that and i fixed it and got 11 thanks
hope you got 1, not 11 yw
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i got 1 i hit the button 2x
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