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Mathematics 19 Online
OpenStudy (anonymous):

(3x-1)2 = 12

OpenStudy (saifoo.khan):

(3x-1)(3x-1) = 12 Try toSolve

OpenStudy (anonymous):

is that squared?

OpenStudy (saifoo.khan):

i guess so.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

oh then you have a choice. you can multiply out first, collect terms, set equal zero and solve or just bust through to the answer. your choice

OpenStudy (anonymous):

all the problems i have are squared

OpenStudy (anonymous):

\[(3x-1)^2=12\] \[3x-1=\pm\sqrt{12}=\pm2\sqrt{3}\] \[3x=1\pm2\sqrt{3}\] \[x=\frac{1\pm2\sqrt{3}}{3}\] is method two

OpenStudy (anonymous):

(x-4)2 + -5, this problem is also squared

OpenStudy (anonymous):

you lost me. is that an equal sign?

OpenStudy (anonymous):

yes it is suppose to be equal

OpenStudy (anonymous):

\[(x-4)^2=-5\]?

OpenStudy (anonymous):

is that it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok if you are working with real numbers there is no solution, since the left hand side is a perfect square and so always bigger than zero, but the right hand side is negative. so no real solution

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

good

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