Question

evaluate:
log2 16 + log2 64

Answer 1

use log property:
log a + log b = log ab

Answer 2

Right.

Answer 3

actually in this case, it would be better to rewrite 16 and 64 as powers of 2

Answer 4

therwise my calculate will work on that.

Answer 5

then use change of base rule

Answer 6

otherwise*

Answer 7

or just say that

\[\log_2(16)=4\] since
\[2^4=16\] and
\[\log_2(64)=6\]
since
\[2^6=64\] and
\[4+6=10\]

Answer 8

change of base???!!!

Answer 9

loga b=logc b/logca