Question

What is one of the real number values that must be excluded from the domain of the function g(x) = 3x-6 / x^2-7x+12?

Answer 1

set the denominator equal zero and solve. that is all the work

Answer 2

\[(x-3)(x-4_=0\]
\[x=3,x=4\] those values are excluded. everything else is ok

Answer 3

What do you mean by excluded do i use 4 or 3 to solve the numerator?

Answer 4

when u have a fraction the denominator cannot b equal to zero or else it isnot within the domain. so if u solve the denominator for zero then u can find where the the domain isnt included

Answer 5

How do I solve it then?

Answer 6

i solved it in step one above. you set the denominator= 0, solve for x, and exclude those values

Answer 7

oooh i get it now

Answer 8

good!