Chem: Calculate the moleseeded to prepare each a. 1.0 L of a 3.0M NaCl solution b. 0.40 L of a 1.0M KBr solution c. 125 mL of a 2.0 M MgCl2 solution
the correct answers are a. 3 moles b. .40 moles c. .25 moles but i don't know how to get them!
a. 3.0M=3moles/liter(1liiter)=3moles b. 1.0M=1moles/liter(.4liter)=.4 moles b. 2.0M=2moles/liter(.125liters)=.25moles
the 3.0M numbers give you how many moles there are per L, so if you multiply by how many liters there are you get the amount of moles
Just to clarify on what physopholy said. You need to cancel L to get the moles: \[1.0 L * 3.0 M = 1.0 L * 3.0 \frac{moles}{L}=3.0 moles NaCL\] \[0.40L*1.0M=0.40L*1.0\frac{moles}{L}=0.40 moles KBr\] \[125ml*2.0M=0.125L*2.0\frac{moles}{L}=0.25 moles MgCl_2\] Note you have to keep the correct Significant figures which is 2 in each case.
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