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factor if possible: c^6 -343
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here, c^6-343=c^6-7^3
Well, 343 is 7 cubed. So we have a difference of cubes as c^6 = (c^2)^3. A difference of cubes is factorised as follows: a^3-b^3 = (a-b)(a^2+ab+b^2) So, applying above, c^6-7^3 = (c^2-7)(c^4+7c^2+49)
(c^2)^3- 7^3
a^3-b^3 = (a-b)(a^2+ab+b^2
whoa!! i'm lost...
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a= c^2 , b = 7
plug ,a= c^2 , b = 7 in a^3-b^3 = (a-b)(a^2+ab+b^2
we have c^6-343=(c^2-7)(c^4+7c^2+49)
got it now.?
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