Question

Please! check my answer.
A gumball machine contains 7 red, 8 orange, 9 purple, 7 white, and 5 yellow gumballs. Tyson buys 3 gumballs. Find each probability,assuming that the machine dispenses the gumballs at random.
P(2 white, 1 purple)
(7/36)*(6/35)*(9/34) = ?

Answer 1

Looks good

Answer 2

Good work man

Answer 3

since order doesn't matter, use combinations
total combinations = 36 Choose 3
\[P = \frac{\left(\begin{matrix}7 \\ 2\end{matrix}\right) *\left(\begin{matrix}9 \\ 1\end{matrix}\right) }{\left(\begin{matrix}36 \\ 3\end{matrix}\right)}\]

Answer 4

your answer only gives the probability of taking a white gumball first and second then the purple one as the 3rd. But what if the purple came out first or second?

Answer 5

or did they give the order? then ignore me :)

Answer 6

the question is white first, next purple

Answer 7

ok you are correct then

Answer 8

my correct?

Answer 9

yes

Answer 10

ty