Question

Solve the equation by taking square roots:

5x^2-3x+2=4x^2-3x+2

Answer 1

The answer on the answer sheet is 0

Answer 2

x = 0

Answer 3

Show work

Answer 4

Simplify
x (5 x-3)+2 = x (4 x-3)+2
x^2 = 0
x = 0

Answer 5

x^2 -3x + 3x + 2 - 2 = 0
x^2 = 0
x = 0

Answer 6

How do I go from:
x(5x-3)+2=x(4x-3)+2

Answer 7

expand the the equation on both sides then cancel out
so\[5x^2-3x+3=4x^2-3x+2\]
then take away all like terms
\[5x^2-3x=4x^2-3x\]

\[x^2=0\]

Answer 8

should be +2 sorry on the LHS