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Mathematics 14 Online
OpenStudy (aravindg):

The number of roots of the equation (x+4)(x+2)(x-5)=(x-2)(x-3)(x+6) are

OpenStudy (anonymous):

x=38

OpenStudy (anonymous):

Quadratic (he said without working it out).

OpenStudy (anonymous):

sorry.

OpenStudy (anonymous):

there will be 2 roots. If you multiply everything out on both sides, you with end up with cubic polynomials. But the x^3 term will cancel out on both sides, leaving a quadratic (like estudier said :))

OpenStudy (aravindg):

wow its discriminant is greater than 0?

OpenStudy (aravindg):

can you open the brackets for me?

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