Question

In the problems 1 to 4, write the expression |x-2|+|x-5| without the symbols of "Absolute Value", if x are in the intervals: 1. (-∞, 1) 2. (7, ∞) 3. (3, 4] 4. [2, 5]

Answer 1

can't wait to see this!

Answer 2

if x-2>0 or x>2 then |x-2|=x-2
if x-2<0 or x<2 then |x-2|=-(x-2)
if x-5>0 or x>5 then |x-5|=x-5
if x-5<0 or x<5 then |x-5|=-(x-5)

-(x-2) x-2 x-2
-(x-5) -(x-5) x-5
---------|-------|--------
2 5

Answer 3

so (-inf,1) we have -(x-2)-(x-5)

Answer 4

(7,inf) we have x-2+x-5

Answer 5

(3,4] we have x-2-(x-5)

Answer 6

1. x<1 2. 7<x 3. 3<x<=4 4. 2<=x<=5

Answer 7

[2,5] we have x-2-(x-5)

Answer 8

wait something is wrong

Answer 9

no you right, the first one is -2x-7

Answer 10

wait i think it is right lol

Answer 11

the first one is -2x+7 i think you forgot to distribute the negative 1

Answer 12

so (-inf,1) we have -(x-2)-(x-5)=-x+2-x+5=-2x+7

Answer 13

(7,inf) we have x-2+x-5=2x-7

Answer 14

oh yes, thanks!

Answer 15

(3,4] we have x-2-(x-5)=x-2-x+5=-2+5=3

Answer 16

yes it is

Answer 17

i cant give you more medals :(

Answer 18

lol its k