Question

Max and jack each throw a die. find the probability that:

(a) the number thrown by max is greater than the number thrown by jack.

Answer 1

there are many possible cases

Answer 2

let jack thrown 1, then max can throw 2,3,4,5,6

Answer 3

i understand that but how do you work out the probability for it?

Answer 4

i tried multiplying the possibilities but the answer wasn't right

Answer 5

the answer should be = 5/36+8/36+9/36+8/36+5/36 =35/36

Answer 6

thats not the answer. its 5/12

Answer 7

thats not the answer. its 5/12

Answer 8

thats not the answer. its 5/12

Answer 9

count

Answer 10

it is only the statement of this question that makes it confusing. suppose you just said
"toss a red and a green die. what is the probability that the green one is larger?"

Answer 11

Jack can throw one of these:

1, 2, 3, 4, 5, 6

For each of Jack's throws, there's a probability that Max will throw a larger number associated to it, as follows:

1 - 5/6
2 - 2/3
3 - 1/2
4 - 1/3
5 - 1/6

Add those probabilities and you'll obtain:

1/2

Answer 12

1/2 isn't the answer though

Answer 13

roll two dice, 36 possible outcomes. the ones where the second one is bigger are
\
(1,2).(1,3).(1.4),(1,5),(1,6)
(2,3),(2,4),(2,5) (2,6)
(3,4),(3,5),(3,6)
(4,5),(4,6)
(5,6)

Answer 14

oh i see

Answer 15

when i count them i get 15, and
\[\frac{15}{36}=\frac{5}{12}\] is the answer i get

Answer 16

thats correct thank you:)

Answer 17

remember when you use 2 dice you do not need any fancy formulas. only 36 elements, just count the ones you want. you can use it to CHECK formula, but you can always count!

Answer 18

ok got it:) thank you

Answer 19

yw