What are the x and y intercepts of the quadratic equation y= 2x^2 -8x + 6?

1) x: (-3,0) and (-1,0)
y: (0,3)

2) x: (-3,0) and (-1,0)
y: (0,6)

3) x: (-3,0) and (-1,0)
y: (0,3)

4) x: (3,0) and (1,0)
y: (0,6)

Question

What are the x and y intercepts of the quadratic equation y= 2x^2 -8x + 6?

1) x: (-3,0) and (-1,0)
    y: (0,3)

2) x: (-3,0) and (-1,0)
    y: (0,6)

3) x: (-3,0) and (-1,0)
    y: (0,3)

4) x: (3,0) and (1,0)
    y: (0,6)

anonymous · Answer

4

anonymous · Answer

y - intercept: x = 0, so y = 6

anonymous · Answer

x - intercept, set 
$$2x^2-8x+6=0$$ solve for x

anonymous · Answer

first divide to 2 to get 
$$x^2-4x+3=0$$ then 
$$(x-3)(x-1)=0$$ so 
$$x-3=0$$
$$x=3$$ or 
$$x-1=0$$
$$x=1$$

anonymous · Answer

number 4 is right

anonymous · Answer

to find x-intercept, find the solution to 2x^2 -8x + 6=0
So the x-intercepts are 3 and 1
and to find the y-intercept, set all the x values to zero and you have 6.