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point slope: containing (-2,6) and having slope -3
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again?
my paper says to give the standard form , graphing form , and point slope idk i guess
\[y-y_1=m(x-x_1)\] \[m=-3, x_1=-2,y_1=6\] \[y-6=-3(x+2)\] \[y-6=-3x-6\] \[y=-3x\]
the one i wrote is slope-intercept form, maybe "graphing form"
standard form of a line is Ax+By=C point-slope form of a line is y-y1=m(x-x1) graphing form is probably slope-intercept form, which is y=mx+b
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point slope form is \[y-6=-3(x+2)\]
standard form is \[3x+y=0\]
y=-3x is the equation and graph for this equation is
this one
i just need the point slope now like how do i plot the numbers given?
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y=-3x + 0 is in point slope form with slope is -3 and y intercept is 0
how you get that?
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