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Mathematics 22 Online
OpenStudy (anonymous):

Can someone please help me with the attachment??

OpenStudy (anonymous):

OpenStudy (anonymous):

it will take time... atleast one day !

OpenStudy (anonymous):

That will be ok, it's not due until tomorrow. Thanks

OpenStudy (anonymous):

inshaAllah i will try ... it at home after my classes are over !!!

OpenStudy (across):

Attachments are not good overall :P People don't like them, and I could throw you a fork bomb with no problem :P (it's a computer science thingy that can cripple your pc for fun)

OpenStudy (anonymous):

i cant open the document

OpenStudy (anonymous):

just click it !

OpenStudy (anonymous):

Suppose you are an event coordinator for a large performance theater. One of the hottest new Broadway musicals has started to tour and your city is the first stop on the tour. You need to supply information about projected ticket sales to the box office manager. The box office manager uses this information to anticipate staffing needs until the tickets sell out. You provide the manager with a quadratic equation that models the expected number of ticket sales for each day x. ( is the day tickets go on sale). a. Does the graph of this equation open up or down? How did you determine this? b. Describe what happens to the tickets sales as time passes. c. Use the quadratic equation to determine the last day that tickets will be sold. Note. Write your answer in terms of the number of days after ticket sales begin. d. Will tickets peak or be at a low during the middle of the sale? How do you know? e. After how many days will the peak or low occur? f. How many tickets will be sold on the day when the peak or low occurs? g. What is the point of the vertex? How does this number relate to your answers in parts e. and f? h. How many solutions are there to the equation ? How do you know? i. What do the solutions represent? Is there a solution that does not make sense? If so, in what ways does the solution not make sense?

OpenStudy (anonymous):

i done a similar problem to this, way back in time, where is the equation that goes with it?

OpenStudy (anonymous):

if you can provide me with that, i can do the problem for you now

myininaya (myininaya):

a is easy it is open down since the coefficient of x^2 is negative

OpenStudy (anonymous):

can someone paste the equation, cause i cant see it

myininaya (myininaya):

T=-0.2x^2+12x+11 i think that is right

myininaya (myininaya):

yep T is tickets

myininaya (myininaya):

so b) what happens to T as x gets large

OpenStudy (anonymous):

okay, then b is also easy because the number of ticket sales goes down to zero, as x gets larger

myininaya (myininaya):

remember this parabola is open downward so as get larges T gets small

myininaya (myininaya):

as x gets large T gets small*

OpenStudy (anonymous):

Heres the equation. Tickets =-0.2^2+12x+1

myininaya (myininaya):

i thought it was 11 at the end?

OpenStudy (anonymous):

to determine the last day tickets will be sold we set the equation to equal 0, so :x = [-12 +- sqrt(144-4*-0.2*11)]/(-0.4) x = [-12 +- sqrt(152.8)]/(-0.4) We take the psositve solution: x = [-12-12.36]/-0.4 x = 60.9 days On the 61st day, the ticket sales go to zero

OpenStudy (anonymous):

Now, for d, we are looking for the tickets sales during the middle of the sale, so we look at the vertex of the parabola. Since it opens down, we know we have a maximum. Which means the tickets sales peak.

OpenStudy (anonymous):

After how many days will the peak occur, this can be determined by finding the x coordinate of the vertex, for this we use (-b)/(2a), After plugging in the numbers we get 30, so on the 30th day the peak will occur

OpenStudy (anonymous):

I'm sorry it is 11 at the end.

OpenStudy (anonymous):

thats fine, i assumed it was 11:)

OpenStudy (anonymous):

Can someone please help me answer F-I? I really appreciate all the help so far. Thanks

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