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Mathematics 9 Online
OpenStudy (anonymous):

find the domain and range of f(x)=sinx with step by step

OpenStudy (anonymous):

-infinity to +infinity

OpenStudy (anonymous):

because domain for any function is define for what value it is define.... or it is shown in x axis

OpenStudy (anonymous):

Domain: \(\mathbb{R}\) Range: \(\left\{x | x \in [-1, 1]\right\}\)

OpenStudy (anonymous):

how to find range of function how -1 ,1 came

OpenStudy (anonymous):

The sine function is bounded above by 1 and bounded below by -1

OpenStudy (anonymous):

if i say domain and range of y=x2+x-1/x2-x-1

OpenStudy (anonymous):

Do you mean this: \[\frac{x^2+x-1}{x^2-x-1}\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

excuse me can anyone help me in my above problem

OpenStudy (anonymous):

The sin(x) just goes between -1 and 1. Just look at a unit circle, its how its defined.

OpenStudy (anonymous):

Start plugging in values every p/3,p/4,pi/6. Look at the min and max. 1 max -1 min

OpenStudy (anonymous):

In the graph u see if u put any real value for x there is some result so domain is all real numbers but for the range u see the graph only moves from 1 to -1 so range is [-1,1]

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