find the domain and range of f(x)=sinx with step by step
-infinity to +infinity
because domain for any function is define for what value it is define.... or it is shown in x axis
Domain: \(\mathbb{R}\) Range: \(\left\{x | x \in [-1, 1]\right\}\)
how to find range of function how -1 ,1 came
The sine function is bounded above by 1 and bounded below by -1
if i say domain and range of y=x2+x-1/x2-x-1
Do you mean this: \[\frac{x^2+x-1}{x^2-x-1}\]
yes
excuse me can anyone help me in my above problem
The sin(x) just goes between -1 and 1. Just look at a unit circle, its how its defined.
Start plugging in values every p/3,p/4,pi/6. Look at the min and max. 1 max -1 min
In the graph u see if u put any real value for x there is some result so domain is all real numbers but for the range u see the graph only moves from 1 to -1 so range is [-1,1]
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