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Mathematics 19 Online
OpenStudy (anonymous):

11√6/√98 simplify

OpenStudy (anonymous):

11sqrt{3}/7

OpenStudy (anonymous):

not sure what sqrt means

OpenStudy (anonymous):

sqrt{98} = 7sqrt{2}

OpenStudy (anonymous):

sqrt means the square root, or x^(1/2)

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

howd u get 7√2 from 11√6

OpenStudy (anonymous):

√98 = √49 * √2 = 7√2 11√6/√98 = 11*7 *√12 11*7*2√3 154√3

OpenStudy (anonymous):

\[11\sqrt{6}/\sqrt{49*2}\]

OpenStudy (anonymous):

11sqrt{6}/7sqrt{2} We can't have a sqrt in the denominator, so we multiply by sqrt{2}/sqrt{2} 11sqrt{6}sqrt{2}/14 Then, simplify

OpenStudy (anonymous):

\[11\sqrt{3}/7\]

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