i think the problem was sin(2x+3)=cos(30-x) and we want to find the minimal value of x using the factor theorem does this look right joe?
i found a solution but i don't how to use the factor theorem like that one guy asked for
yeah thats right, is there something more to this problem? i thought we solved it?
he wanted minimal value for x
and i have no clue how to use factor theorem to solve this
oh oh. i think by factor theorem he meant sum/difference formulas, it would be a long drawn out process >.<
is that what you were attempting?
yes, and i got tired lol >.<
lol so i got x=pi/2-75
your solution was swift and fast, like a ninja.
but i don't know how i'm suppose to show its minimal value
there are other solutions
i guess i could do it my way and see what i get >.< give me an hour lol
Is the angles in degrees here
its in radians
inside the sin was 2x+45 tw
im sry, 2x-45
i remember negative root 2 over 2's popping up
roshan this is what i did earlier \[\sin(2x+45)=\sin(\frac{\pi}{2}-(30-x))\] \[2x+45=\frac{\pi}{2}-(30-x)\]
thanks joe
\[2x-x=\frac{\pi}{2}-30-45\] \[x=\frac{\pi}{2}-75\]
trig functions are funky how do you know you have all the solutions
and i know i don't
this is too long, i dont wanna do it >.<
ok don't do it lol
your solution looks funny o.O are those numbers in degrees?
no
lol thats what rosahan asked lol
we also have the solution \[x=-\frac{3\pi}{2}-75\]
75 almost like 12(2pi)....its like your flying around the unit circle redundantly o.O
if that is indeed radians.
i also checked it out wolfram to see if the solution worked and it did i think we can come up with something not so ugly
maybe not i'm not sure
\[x=\frac{5\pi}{2}-75 \] is another solution i want to generalize my answer
oh i see how to :)
whats the pattern?
\[x=(-1)^{n}(2n+1)\frac{\pi}{2}-75, n=0,1,2,3,4,5,6...\]
now since this goes on and on there is no way to tell what is the smallest solution
Somehow my teacher told us to change the whole thing to sin theta and move it to one side.
Join our real-time social learning platform and learn together with your friends!