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How to write (2n)! in general form?
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"general form"?
i'm guessing expaneded form?
yeap
2 [ n * (n-1) -------- 3, 2 1 ]
But I want to include n! here in the expanded form
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\[(2n)!=2n(2n-1)(2n-2)...\times n!\]
Why is it satellite? Though I know that n!=n*(n-1)*........2*1
I want to know how?
What about [2(n+1)]! then
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(2n)! isnt 2n! (2n)! is (2n)(2n-1)(2n-2)...(n+1)(n)(n-1)...(2)(1) Examples: n = 3 (2n)! = (2*3)! = 6! = 720 2*3! = 2*6 = 12 totally different.
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