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Show that:- tan 60(tan 170 - tan 140)= 1+tan 170.tan140
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sqrt(3) tan(170°)-sqrt(3) tan(140°) = tan(140°) tan(170°)+1
That is one way to change it around a bit.
\[\tan(60)(\tan170-\tan140)*\frac{1+\tan(170)\tan(140)}{1+\tan(170)\tan(140)}\] \[\tan(60)\tan(170-140)(1+\tan(170)\tan(140))\] \[\tan(60)\tan(30)(1+\tan(170)\tan(140))\] \[(\sqrt{3})(\frac{1}{\sqrt{3}})(1+\tan(170)\tan(140)) = 1+\tan(170)\tan(140)\]
using the fact that: \[\tan(A-B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)\tan(B)}\]
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