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14x^2-686/4x^2-196 can someone help please
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\[\frac{14x^2-686}{4x^2-196}=\frac{7-686}{2-196}=\frac{-679}{-194}\]\[\frac{7}{2}\]
thank you nancy, I think I understand this better now.
Another way to do it is take the GCF, giving you \[14(x^2-49)\div(4(x^2-49)\] Since the top and bottom both have a (x^2-49), they can cancel. This will leave you with 14/4, which simplifies to 7/2 or 3.5
thank you entezflare
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