Question

Mike went to a football game with his family. They bought 5 boxes of popcorn, 3 programs and spent $41. Sean's family went to the same game, bought 3 boxes of popcorn, 2 programs and spent $26. How much does each program cost at the game?

Answer 1

who was playing?

Answer 2

lol

Answer 3

ok
\[5x+3y=41\]
\[3x+2y=26\]

Answer 4

let the cost be x and y for popcorn and program

5x + 3y=41
2x + 2y = 26

Now solve them

Answer 5

but 3 dosnt gointo 26

Answer 6

\[10x+6y=82\]
\[-9x-6y=-78\]
add to get
\[x=4\]

Answer 7

ah sorry 3x+2y = 26

Answer 8

y=7

Answer 9

ok i used your formula i agree

Answer 10

and since
\[x=4\] we know
\[5\times 4+3y=41\]
\[20+3y=41\]
\[3y=21\]
\[y=7\]

Answer 11

popcorn is $3, programs are $7 and it must be a high school game because otherwise these prices would be doubled at least

Answer 12

ok thank you

Answer 13

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to x from the first equation is substituted into the second equation.
x + y = 2
3x + 2y = 9

Answer 14

does anyone want to give this a shot