If 5 sin theta = 3. Find sec theta+tan theta/sec theta - tan theta
\[\sin(\theta)=\frac{3}{5}\] so you have a right triangle with opposite side 3, adjacent side 4 and hypotenuse 5
draw the triangle and you can find all other trig funcitons
thanx! :D
if you get stuck on any let me know
can you solve and show if you dont mind?
\[\sin \theta = 3/5 =opposite/hypotenuse\]
use pythagoras theorem to find the third side
ok so your hypotenuse is 5, opposite is 3 adjacent is 4 here are all of them right from the triangle
\[\sin(\theta)=\frac{3}{5}\] \[\cos(\theta)=\frac{4}{5}\] \[\tan(\theta)=\frac{3}{4}\]
now for the reciprocals \[\csc(\theta)=\frac{5}{3}\] \[\sec(\theta)=\frac{5}{4}\] \[\cot(\theta)=\frac{4}{3}\]
notice how odd this is because you are asked to evaluate a function without actually knowing what the input is. you rely on the ratio of the triangle to get it, once you have memorized that whole "opposite over hypotenuse" business
Join our real-time social learning platform and learn together with your friends!