Question

I need help to solve a problem...

Answer 1

Post it in here and someone will help :)

Answer 2

yes?
Post it..
we will help you..

Answer 3

\[\left(\begin{matrix}x ^{-3} \\ y ^{4}\end{matrix}\right) ^{-3}\]

Answer 4

step by step to get the answer

Answer 5

Alright first step you can re-write that as
\[\left(\begin{matrix}y^{4} \\ x^{-3}\end{matrix}\right)^3\]
By knowing that a negative power simply means 1 over the brackets, which allows us to invert them

Answer 6

so i just make the -3 a positive that is out side of the paraenthesis?

Answer 7

the answer i came up with is \[\left(\begin{matrix}y ^{28} \\ x ^{-21}\end{matrix}\right)\]

Answer 8

is this a matrix? or is it
\[(\frac{x^{-3}}{y^4})^{-3}\]

Answer 9

if it is the second one, multiply the exponents to get
\[\frac{x^9}{y^{-12}}\]

Answer 10

then get rid of the negative exponent by writing
\[x^9y^{12}\]

Answer 11

so it doesn't go into a fractional form b/c it dont have a - right?

Answer 12

1/y^-12 is same as y^12...