3tan^3x = tanx
x = 0, -pi/6, pi/6 Rdians
Find all the solutions in the interval (0, 2pi).
Pk, can you explain your answer?
x = 0, -30, 30 Degrees
3tan^3(x) = tan(x) 3tan^2(x) = 1 tan^2(x) = 3 tan (x) = root 3 x= pi/3, 4pi/3
Factor, like myininaya did, then set each part equal to zero and use the unit circle to see where it is equivalent. Then use ASTC to find all solutions.
Ok. Thank you.
my page is going so slow
it should be: \[3\tan^2(x)-1\]
yep you are right
otherwise, brilliant!
\[3\tan^3x-tanx=tanx(3\tan^2x-1)=0\]
\[tanx=0=> x=2n \pi , x=n \pi , n \in \mathbb{Z}\] \[\tan^2x=\frac{1}{3}=> tanx=\pm \sqrt{\frac{1}{3}}=\pm \frac{1}{\sqrt{3}}=\pm \frac{\sqrt{3}}{3}\]
So is it fine if I just keep it as my answer but switch what joemath said?
i redid with what joe said
but you need to solve that last equation for x
ok ok, thanks.
i didn't realize you said find solutions in (0,2pi) so the first equation we just have the answers x=pi
the second equation i would use a calculator
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