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Mathematics 17 Online
OpenStudy (anonymous):

3tan^3x = tanx

OpenStudy (anonymous):

x = 0, -pi/6, pi/6 Rdians

OpenStudy (anonymous):

Find all the solutions in the interval (0, 2pi).

OpenStudy (anonymous):

Pk, can you explain your answer?

OpenStudy (anonymous):

x = 0, -30, 30 Degrees

OpenStudy (anonymous):

3tan^3(x) = tan(x) 3tan^2(x) = 1 tan^2(x) = 3 tan (x) = root 3 x= pi/3, 4pi/3

OpenStudy (anonymous):

Factor, like myininaya did, then set each part equal to zero and use the unit circle to see where it is equivalent. Then use ASTC to find all solutions.

OpenStudy (anonymous):

Ok. Thank you.

myininaya (myininaya):

my page is going so slow

OpenStudy (anonymous):

it should be: \[3\tan^2(x)-1\]

myininaya (myininaya):

yep you are right

OpenStudy (anonymous):

otherwise, brilliant!

myininaya (myininaya):

\[3\tan^3x-tanx=tanx(3\tan^2x-1)=0\]

myininaya (myininaya):

\[tanx=0=> x=2n \pi , x=n \pi , n \in \mathbb{Z}\] \[\tan^2x=\frac{1}{3}=> tanx=\pm \sqrt{\frac{1}{3}}=\pm \frac{1}{\sqrt{3}}=\pm \frac{\sqrt{3}}{3}\]

OpenStudy (anonymous):

So is it fine if I just keep it as my answer but switch what joemath said?

myininaya (myininaya):

i redid with what joe said

myininaya (myininaya):

but you need to solve that last equation for x

OpenStudy (anonymous):

ok ok, thanks.

myininaya (myininaya):

i didn't realize you said find solutions in (0,2pi) so the first equation we just have the answers x=pi

myininaya (myininaya):

the second equation i would use a calculator

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