Solve 4x^2=4 What are the solutions? what are the intercepts of f(x)=4x^2-8?
First one: 4x^2=4 now divide both sides by 4 and we get: x^2=1 now take the square root of both sides and we get: x=plus or minus 1
Second: is the same as the first, x intercepts can be solution Do, the same process as i did for the first one, you should get : plus or minus \[\sqrt{2}\]
so (1+sqrt2),(1-sqrt2)? is this correct?
for which one?
the second one is only plus or minus sqrt 2
The top? I'm confused lol
oh
4x^2=4 is only plus or minus 1
f(x)=4x^2-8 is only plus or minus sqrt 2
so -1,2?
for the first part?
where die you get a two from?
the intercepts for the first part are: +1 and -1
lol told u I was confused I see now
the intercepts for the second one are : +sqrt2 and -sqrt2
got it!
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