another cal question: If f is differentiable function such that f(x) is never 0 and int(f(t),t=0..x)=[f(x)]^2 for all x, find f.
\[\int\limits_{0}^{x}f(t) dt=[f(x)]^2\]
that is what that one part says
i need to massage my wrist i will be right back
do you want me to tell you the first thing i would do?
Yes
take derivative of both sides
Differential equations?
yes and we should be able to solve the differential equation pretty easily
\[f(x)=2f(x)f'(x)\]
\[f'(x)=\frac{1}{2}\]
then integrate both sides and then you have f(x)
this problem was too easy let me see if i find a harder one
so f(x) would be 1/2 x +C ?
yep
:)
so f(t)= 1/2 t right?
\[\int\limits_{0}^{x}(\frac{1}{2}t+C)dt=\frac{1}{2}*\frac{t^2}{2}+Ct+D=\frac{t^2}{4}+Ct+D\] we want this to be equal to \[(\frac{1}{2}t+C)^2=\frac{1}{4}t^2+tC+C^2\] so we need D=C^2
oops just imagine all those t's are x's
where is the D coming from?
its a constant i added the constant after integrating
you don't need it on a definite integral
oops you are right
imagine there is no D
i think we need to take C to be zero like imaranmeah said
then what about this ... "f(x) is never 0"
because integral of 1/2 t is t^2 evalatuated from 0 to x so x^2 but that's not it
what about when x is zero
f(x)=1/2 *x
oh then f would be 0 if x is 0 so this function is wrong
ok so maybe this one is a little harder than i thought
they probably meant to say that f(x) can't be identically zero
do you have the james stewart 6th edition cal book?
the one with big ring on it?
yes
a huge \[\int\limits_{}^{}\] symbol like this is on that cover yes imranmeah why is this book so popular?
i don't about this question zarkon it says never zero
I only have the 7th edition here at home...my 6th edition is in my office
page 345 in my book who knows you might have the same question
what section
I also have the 7th edition only :/
problem plus after chapter 5
problems plus*
i don't see that problem
number 3
my #3 has stuff with integrals of exponential functions
it sounds like they don't want f(x) to be 0 ever almost if it were an exponential function or a positive constant
but exponential wouldn't work
the question has no solution as written since \[0=\int\limits_{0}^{0}f(t) dt=[f(0)]^2\]
you are right i don't think they put the answers to the problem plus in the back :(
they dind't want a student to write \[f(x)=0\] as a solution
didn't
they just worded it incorrectly
so maybe they should have said f(x) is not identically zero
like you said
yes...then the above solution... x/2 works
maybe this is why its not in the 7th edition
maybe ;)
thats why joe hates calculus
lol
i hate calculus. >.>
I love calculus :)
joe why you hate cal so much?
i love linear algebra.
doesn't linear algebra use calc?
i guess i should be a little more specific. What i hate in calculus is really just integration. I like everything else.
so you hate integrating something like x^2
no, linear algebra doesnt use calc, its the other way around! Differentiation is a Linear Transformation on the vector space of functions: \[\frac{d}{dx}(0) = 0\] \[\frac{d}{dx}(af(x)+g(x)) = a\frac{d}{dx}f(x)+\frac{d}{dx}g(x)\]
I love calculus, but I see why someone would hate it after being asked to integrate: \[\int{x^5sin(x)dx}\]Tee hee
the same can be said for integration as well! so there are matrices that represent these transformations. Who needs calc? i'll use the matrix thank you very much :P
i think they should teach remedial linear algebra before algebra i think easy general things should be thought first
Transformation; is it like jacobian?
taught* i hat english i swear
hate*
lol
we need to "asianize" americans
@imran yes, the jacobian matrix is also a linear transformation i believe.
Yeah, I hated those; I forgot it during final . Had to cheat from person sitting ahead
you do what you gotta do lol
How in the world can you cheat from the guy in front of you without being seen? xd
the class is on incline. So we are higher than people sitting infront of us
lol I've seen that, I did better because no one notice
When I am in library , I think of that Mr.Bean scene
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