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Solve the equation below for x using any method: 2x^2+3x+6=0 A. (-3±i√39)/4 B. 2±3i C. x=-3;x=2 D. x=3±√57
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Hello Kassia : )
hello :)
Hi Kassia! I am back!
A. (-3±i√39)/4
2x^2 + 3x + 6 = 0 for this purpose is best solved using the quadratic formula. -b +- sqrt(b^2 - 4ac)/2a. a = 2 b = 3, c = 6. The answer is A. Hope this helps. If it does, please choose good answer. Visit my website at http://www.tutorsean.net for free math training videos.
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\[x = \frac{ -3 \pm \sqrt{9 - 4*2*6}}{2}\] \[x = \frac{ -2 \pm i\sqrt{39}}{2}\] A
sorry 3 not 2 typo
and 4 in denominator 2*2 = 4 lot of typo sorry
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