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Mathematics 17 Online
OpenStudy (anonymous):

Puzzle time! Which is a better fit (i.e., results in less wasted space), a square peg in a round hole or a round peg in a square hole? (From http://richardwiseman.wordpress.com/2011/08/12/its-the-friday-puzzle-123)

OpenStudy (anonymous):

oh I love puzzle time

OpenStudy (sgvxfcbxvxv):

circle

OpenStudy (mimi_x3):

hmm.. a square peg in a round whole

OpenStudy (mimi_x3):

hole*

OpenStudy (anonymous):

Puzzle time requires either a conceptual, logical, or numerical solution :D

OpenStudy (anonymous):

In any case, my calculations say the opposite is true (not that I'm necessarily right, this is part of why solutions are needed ;) )

OpenStudy (mimi_x3):

what do yu mean by conceptual, logical or numerical solution ? So there's like working out for the puzzle ? Cant it be a guess lmao

OpenStudy (anonymous):

If lets say hole is of diameter 2d then radius d area pi*d^2, now the square's diagonal must be 2d hence side is sqrt2d hence area should be 2d^2 Now when cirlce in square then 2d = square side diameter 2d and radius d pid^2 area of circle and 4d^2 4d^2 - pi d^2 < pi d^2 - 2d^2 4 - 3.14 < 3.14 - 2 .86 < 1.14 circle in square

OpenStudy (anonymous):

i am the winner yaay yaay

OpenStudy (akshay_budhkar):

no i am the winner!

OpenStudy (anonymous):

It can't be a guess, no. In this case, conceptual, or logical solutions won't work, but in general they can be used at puzzle time.

OpenStudy (mimi_x3):

lolss , i never realised maths is involved in the puzzle , gosh im stupid xDD

OpenStudy (akshay_budhkar):

hi dalvoron.. seeing you after long time..

OpenStudy (anonymous):

me too Hi dalvoron

OpenStudy (anonymous):

I think I should give it to Ishaan! I worked it out on the basis of percentage space wasted, but the question doesn't specifically ask for that. Well done!

OpenStudy (anonymous):

Also hi.

OpenStudy (akshay_budhkar):

where is ishaans answer?

OpenStudy (anonymous):

The post that starts with "If lets say hole is of diameter 2d then radius d"

OpenStudy (akshay_budhkar):

i cant see it! wait i will reload

OpenStudy (anonymous):

isnt it square in a round hole = 2/pi peg in square hole = pi/4

OpenStudy (akshay_budhkar):

ya i got it its d same i was replying thank god you declared him the winner:)

OpenStudy (anonymous):

I mean: ratio of square area to round hole area = 2/pi ratio of circle area to square hole area = pi/4

OpenStudy (anonymous):

I think fiddlearound deserves a medal for that, good job!

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