PLEASE HELP ME ANSWER THESE QUESTIONS FOR THIS IMAGE. -PICTURE IS UNDER THIS POST-
This exact question came up earlier today.
REALLY? SOMEONE ELSE ASKED IT?
Yes, this exact same question. Down to the letter.
THATS WEIRD LOL
yep some christine person
invited us to twiddla to have us do it... probably same workbooks.
oh ok.. could you guys help me do this?
Formula for area and circumference were given in the previous answer. The question of arclength is this: 100% of the circumference is pi times diameter. (that's a full 360 degrees). Now, you're only given 72%, so what percent of the full 360 degrees is that?)
do I multiply 72 and 360??
the entire circle q area is\[225\pi\] and the diameter of the circle is \[30\pi\] the last question in the picture wants you to find the arclength of the circle, which is 72/360 degrees of the circle. You will find it to be \[5\pi\]
oops. it's \[6\pi\]
you don't multiply them. you multiply \[\frac{72}{360}\] by the circumference of the circle which is \[30\pi\]
what about the area?
225?
and the area is 15?
to find the area, you need to use the equation \[Area = \pi r^2\] where r is given to be 15 inches
i mean the length of DE
the length of DE is not actually 15 inches. It's the length of DQ and QE
so when it says calculate the are of the circle Q the answer is 15 pi? the circumference=30 the length of DE=15?
oh ok
so what would the length of DE be?
once you find the circumference of circle Q (30pi) you multiply it by \[\frac{72}{360}\]
to get the arclength of DE. for the length of the segment DE... you need to work with triangles.
the length of DE=6?
how did you find that?
72/360x30?
yeah. that's the answer to the last question in the picture, the length of arc DE :-D
thanx! so everything else is right? number 4 is a)15 and number 5 is b)30?
number 5 is right. number 4 is wrong though. check my answer again
15 squred so its 225?
I got 225 pi using the formula for area of a circle first I squared 15 to get 225, then I multiplied it by pi.
choice d.
ok,thanx ALOT..there are 2 more question to this image im going to be posting in like 5 seconds..if you could help me out that would be awesome
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