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Simplify by removing factors of 1. p^2-4 / (p+2)^2
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Ah okay :)
\[\frac{p^2-4}{(p+2)^2}\]
(p-2)/(p+2)
factor the numerator and cancel. steps are \[\frac{9^2-4}{(p+2)(p+2)}=\frac{(p+2)(p-2)}{(p+2)(p+2)}=\frac{p-2}{p+2}\] what hero said!
that 9 should be a 'p'
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Wow, somebody took my suggestion for "legend" congrats
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