PLEASE HELP ME ANSWER THESE QUESTIONS FOR THIS IMAGE. -PICTURE IS UNDER THIS POST-
\begin{array}l\color{#FF0000}{\text{Y}}\color{#FF7F00}{\text{o}}\color{#FFFF00}{\text{u}}\color{#00FF00}{\text{ }}\color{#00FF00}{\text{p}}\color{#0000FF}{\text{o}}\color{#6600FF}{\text{s}}\color{#8B00FF}{\text{t}}\color{#FF0000}{\text{,}}\color{#FF7F00}{\text{ }}\color{#FF7F00}{\text{I}}\color{#FFFF00}{\text{ }}\color{#FFFF00}{\text{a}}\color{#00FF00}{\text{n}}\color{#0000FF}{\text{s}}\color{#6600FF}{\text{w}}\color{#8B00FF}{\text{e}}\color{#FF0000}{\text{r}}\end{array}
\[\frac{126}{360}*C = 14\pi\] So to find the circumference of the circle we solve for C using algebra. \[C = 40\pi\]
OK so 9 is 40?
yes. 40pi
would #10 be a?
yep it's 10pi
ok! what about 11 and 12?
for 11 we write an equation to solve for x, where x is the measure of angle TRS \[ \frac{x}{360}*18\pi= 7\pi\] \[x = 140\] so for 11 the answer is 140
for 12 we use another equation \[\frac{135}{360}*\pi(\frac{D}{2})^2 = 73.5\pi\] \[D = 28\]
so for 12 the answer is 28
Thanx ALOT!
Join our real-time social learning platform and learn together with your friends!