Question

(x^2-3x+2)-(3x^2-5x-1) Answer please thanks

Answer 1

hey gurl ;D

Answer 2

-2x^2 +2x +1

Hey! =)

Answer 3

awe, i got it wrong ? I got -3x^4+14x^3-20x^2+7x+2 am i wrong??

Answer 4

Would it not be +3?

+2 - -1?

Answer 5

Your right Chaise! Sorry again =(
UTK fresh all your supposed to do is substract..dont multiply

Answer 6

It's fine, we all make mistakes.

Answer 7

Oh fck lol thanks so much ;D

Answer 8

No problem =)

Answer 9

im sorry i still don't get it step by step please thanks sorry

Answer 10

hello?

Answer 11

(x^2)-3x+2-(3x^2)+5x+1=0
(-2x^2)+2x+3=0
(-2x^2)+2x=3
-2((x^2)-x)=3
(x^2)-x=-3/2
(x^2)-x+3/2=0
Right here I would use the quadratic formula
x= (-b+-Sqrt((b^2)-4ac)/2a
a=1, b=-1, c=3/2
x=1+-sqrt((1^2)-4(1)(3/2))/2(1)
x=(1+-sqrt(6))/2
That is pretty much your answer without using imaginary numbers

Answer 12

Is this multiplying or subtraction??
if it is multiplying (stuff) times -(more stuff) you did it right.
if it is subtraction, (stuff) minus (more stuff) see Kat's answer
See
http://www.wolframalpha.com/input/?i=%28x%5E2-3x%2B2%29*-%283x%5E2-5x-1%29

Answer 13

(x^2-3x+2)-(3x^2-5x-1)
So first we have to distribute the NEGATIVE to (3x^2 - 5x -1)
When we do that we get:
-3x^2 + 5x +1
Now we collect like terms:
(x^2-3x+2 - 3x^2 + 5x + 1)
Collect the x^2s first, by addicng their coeffiencts.
1x^2 - 3x^2 = 6x^2
Now add the coefficents of the x terms only:
-3x + 5x = 2x
Now collect the like terms of constants:
2 + 1 = 3

PUt it all together and get :
-2x^2 + 2x + 3