Question

2y^2-8y+5=0 <--- solve by the quadratic formula , set the equation to "0" first. must be in simplest radical form, show work please

Answer 1

If I solve it, it will only confuse you. I have this crazy idea that all quadratics are factorable

Answer 2

ohh:p

Answer 3

-8+\[8\pm \sqrt{(-8)^2-4(2)(5)}\] Im doing the numerator first

Answer 4

You could have at least posted the actual quadratic formula first

Answer 5

sorry http://en.wikipedia.org/wiki/Quadratic_equation

Answer 6

you solve the inside of square root you will get \[8\pm \sqrt{64-40}\]

Answer 7

\[8\pm \sqrt{24}\]

Answer 8

\[8\pm2\sqrt{6}\]

Answer 9

now all of this is over the denominator 2(2) correct
it simplifies to \[2\pm (\sqrt{6}\div2)\]

Answer 10

thanks