Question

(5x^3 y^6) (6x^2 y^5) simplify how can I do this showing steps to get answer?

Answer 1

To do this equation we must distribute the whole left parentheses.
(5x^3y^6)(6x^2y^5)
Remember when multiply exponents with the same variable, we add them.
30x^5y^11.
I got that by multiplying each common term.
5x6=30
We have our exponents 3 and 2, which give us the exponent of 5.
Since y is not a coefficient we just add our 2 exponents.
Our exponents are 6 and 5, which gives us the exponent of 11.

FINAL ANSWER:
30x^5y^11.

Answer 2

\[\color {green} {\huge{\checkmark}}\]

Answer 3

Your welcome! :D

Answer 4

roseanne! hello

Answer 5

thank you very much!

Answer 6

I checked the answer, so it's good

Answer 7

Hey hero I have a final tom orrow for algebra could u help me a lil bit?

Answer 8

Then give me a medal. :3

Answer 9

um...um...

Answer 10

What time?

Answer 11

is my final?

Answer 12

What time are you doing it, yes.

Answer 13

11:30am

Answer 14

what time zone?

Answer 15

Florida

Answer 16

florida daylight time?

Answer 17

sat will you help me show me steps on these problems

Answer 18

name one

Answer 19

simplify (w^19) ^0 (w^6)

Answer 20

w^6

Answer 21

anything to the power of zero is 1. so ignore that one

Answer 22

you are left with just what hero said,
\[w^6\]

Answer 23

It always will equal to 1 when the exponent is 0.
Regardless of the numbers.

Answer 24

whenever you see
\[b^0\] remember that
\[b^0=1\]

Answer 25

so how is it w^6?

Answer 26

Regardless of terms, always will be 1.

6\[6x ^{0} \]= 1

Answer 27

we go slow.
\[(w^{19})^0=1\]

Answer 28

It is w^6 because
w^6 x 1= w^6.
XD

Answer 29

Any positive rational number times itself will always be the same.

Answer 30

so
\[(w^{19})^0\times w^6=1\times w^6=w^6\]

Answer 31

(Y)

Good job! :3

Anymore quesions?

Answer 32

ok multiply (4x+5) (2x^2-x-3)

Answer 33

first you have to multiply everything in the second parentheses by 4x
\[4x(2x^2-x-3)\]

Answer 34

when you do this, multiply the numbers together, and add one to each exponent. you will get
\[8x^3-2x^2-12x\] is that part clear? we are not done yet

Answer 35

To multiply it
we distribute each term in the left parentheses to the right.
4x2=8
Multiply exponents: 1x2 or 1+2=3
8x^3-4x-12x
Above is the first term distributed to the whole group.
Now the 2nd term.
10x^2-5x-15.

Combine like terms.
8x^3-4x-12+10x^2-5x-15

8x^3-9x-27 is our final answer.

Answer 36

then you have to multiply everything in the second parentheses by 5. you get
\[5(2x^2-x-3)\] which is
\[10x^2-5x-15\]

Answer 37

so in total you have
\[8x^3-2x^2-12x+10x^2-5x-15\]

Answer 38

now you need to combine like terms.
\[8x^3\] has no other like terms because the exponent is 3 and it is the only term with an exponent of 3

Answer 39

\[-2x^2+10x^2=8x^2\] because they are like terms and
\[-2+10=8\]

Answer 40

\[-12x-5x=-17x\] for the same reason, and -15 has no like term. so your "final answer" is
\[8x^3+8x^2-17x-15\]

Answer 41

except that i messed up on the x squared term. hold on

Answer 42

graph the line which is easy but how do I convert y=2x+3 to a point?

Answer 43

hold on one second i made a mistake
\[4x(2x^2-x-3)\] should be
\[8x^3-4x^2-12x\] so your answer above should be
\[8x^3+6x^2-17x-15\]

Answer 44

you do not convert
\[y=2x+3\] so a point. but if you want a point on the line you pick any x, and then find y

Answer 45

for example if i pick x = 1 then i know
\[y=2\times 1+3=2+3=5\] so the point (1,5) is on the line

Answer 46

To convert it to a point:
we use our y intercept and slope.
Let's start with y intercept which is (0,3).

Then use slope (rise/run.)
Our rise is 2/1
From our y intercept we move up the y axis 2 point and to the right one point, which is point (1,5). Then connect the lines.

Answer 47

if i pick x = 2 then i know
\[y=2\times 2+3=4+3=7\] so the point (2,7) is on the line. and so on

Answer 48

subtract (10x^2+7x-2) - (4x^2-2x+2)