Question

What are two numbers for which the sum of there square is 628 and the differance of there squares is 340?

Answer 1

x^2+y^2=628
x^2-y^2=360

Answer 2

solce to get the answer

Answer 3

a^2 + b^2 = 628

a^-b^2 = 340

Answer 4

let the numbers be a,b
given \[a ^{2}+b ^{2}=628\]\[a ^{2}-b ^{2}=340\]
then 2a^2=968
a^2=484
a=22
b=12

Answer 5

damnit Srir beat me :(

Answer 6

who?me?

Answer 7

yeah you answered faster :P How did you know to add 340 to 628?

Answer 8

na.....its not the matter of speed
its the matter of accuracy....see i'm not smart than anyone...so u too won!