Mathematics
17 Online
OpenStudy (anonymous):
factor 6x^2+11x+4
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (saifoo.khan):
thts wrong^
OpenStudy (saifoo.khan):
my answer was correct.
OpenStudy (anonymous):
the thing is he uses this "blank x" technique, familiar?
OpenStudy (anonymous):
Yes.
OpenStudy (saifoo.khan):
i knw.. thts the same thing
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no two factos of 4 and 6 add to 11 >.>
OpenStudy (anonymous):
(x+2) (3+4) ?
OpenStudy (anonymous):
Because your coefficient on the x^2 term is a 6 then it must be one of these forms:
\[(2x + a)(3x+b)\] or \[(6x + a)(x+b)\]
OpenStudy (saifoo.khan):
wrong twalls.
OpenStudy (anonymous):
6x^2+3x+8x+4
3x(2x+1)+4(2x+1)
(3x+4)(2x+1)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (saifoo.khan):
sri, please delete your first answer.
OpenStudy (anonymous):
i have deleted already
OpenStudy (saifoo.khan):
now u did, lol.
OpenStudy (anonymous):
the newest is the right one i think....i hope
OpenStudy (anonymous):
I forgot about 4 and 1 lols!! Yeah tested your sri it's right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (saifoo.khan):
Sri is right this time! :0
OpenStudy (saifoo.khan):
=)
OpenStudy (anonymous):
ok, i think i got it...maybe lol ty!
OpenStudy (anonymous):
Yeah, you don't have it cause they didn't really help you they just gave you the answer.
OpenStudy (anonymous):
You should actually have them explain and make sure you get it before you give them their medals ;p