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Mathematics 21 Online
OpenStudy (anonymous):

factor 6x^2+11x+4

OpenStudy (saifoo.khan):

thts wrong^

OpenStudy (saifoo.khan):

my answer was correct.

OpenStudy (anonymous):

the thing is he uses this "blank x" technique, familiar?

OpenStudy (anonymous):

Yes.

OpenStudy (saifoo.khan):

i knw.. thts the same thing

OpenStudy (anonymous):

no two factos of 4 and 6 add to 11 >.>

OpenStudy (anonymous):

(x+2) (3+4) ?

OpenStudy (anonymous):

Because your coefficient on the x^2 term is a 6 then it must be one of these forms: \[(2x + a)(3x+b)\] or \[(6x + a)(x+b)\]

OpenStudy (saifoo.khan):

wrong twalls.

OpenStudy (anonymous):

6x^2+3x+8x+4 3x(2x+1)+4(2x+1) (3x+4)(2x+1)

OpenStudy (saifoo.khan):

sri, please delete your first answer.

OpenStudy (anonymous):

i have deleted already

OpenStudy (saifoo.khan):

now u did, lol.

OpenStudy (anonymous):

the newest is the right one i think....i hope

OpenStudy (anonymous):

I forgot about 4 and 1 lols!! Yeah tested your sri it's right

OpenStudy (saifoo.khan):

Sri is right this time! :0

OpenStudy (saifoo.khan):

=)

OpenStudy (anonymous):

ok, i think i got it...maybe lol ty!

OpenStudy (anonymous):

Yeah, you don't have it cause they didn't really help you they just gave you the answer.

OpenStudy (anonymous):

You should actually have them explain and make sure you get it before you give them their medals ;p

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