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Mathematics 11 Online
OpenStudy (anonymous):

How do i figure out the common denominator with fractions , I'm confused .

OpenStudy (anonymous):

say u have a problem like this: \[\frac{1}{2}+\frac{2}{3}\]

OpenStudy (anonymous):

you need common denominators to add them

OpenStudy (anonymous):

true but how would i solve it?

OpenStudy (anonymous):

sorry, had to go for a minute

OpenStudy (anonymous):

your denominators are 2 and 3 find the LCM of each. what is the smallest number that 2 and 3 are both factors of? the answer is 6

OpenStudy (anonymous):

Now look at your fractions again

OpenStudy (anonymous):

what times 2 equals 6?

OpenStudy (anonymous):

2*3=6 multiply the denominator by 3 and the numerator by 3

OpenStudy (anonymous):

you get 3/6

OpenStudy (anonymous):

Now look at the second fraction.

OpenStudy (anonymous):

what times 3=6? 2*3=6 so multiply the numerator and the denominator by 2 this time you get 4/6

OpenStudy (anonymous):

And now you have common denominators and can tell that the answer is 7/6, or 1 and 1/6

OpenStudy (anonymous):

Hope this helps!

OpenStudy (anonymous):

so i add 4/6 and 3/6?

OpenStudy (anonymous):

how would i get 1 1/6? sorry i know I'm difficult .

OpenStudy (anonymous):

No prob. convert the improper fraction to a mixed number

OpenStudy (anonymous):

\[\frac{7}{6}=1 \frac{1}{6}\]

OpenStudy (anonymous):

How many times does 6 go into 7?

OpenStudy (anonymous):

1 time. So take one whole- one 6/6- out of the equation, you are left with 1/6

OpenStudy (anonymous):

since the 6/6 is a whole, it becomes a 1, and you have 1/6

OpenStudy (anonymous):

if your fraction was, say, 14/6

OpenStudy (anonymous):

then 6 goes into 14 two times \[\frac{6}{6}+\frac{6}{6}+\frac{2}{6}=\frac{14}{6}\]

OpenStudy (anonymous):

so you'd have 2 2/6 got it?

OpenStudy (anonymous):

yea , thanks man how could i add you i don't know how to use this i just needed help with this pellet.

OpenStudy (anonymous):

Your welcome

OpenStudy (anonymous):

but umm how do i do the subtraction

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