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(n+1)!-(n)! = ??
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n!(n+1)-n! =n!(n+1-1) =n!(n)
is this what you meant to write last time?
lol
yea..i got the sign wrong..sorry
but i didin't understand this One
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how did u do it ??
\[(n+1)!=(n+1) \cdot n! \] do you understand this part?
yup
ok so we have \[(n+1)n! \cdot -n!=n!(n+1-1)\] right?
yeah right
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that dot isn't suppose to be there
\[=n!(n)\]
1-1=0
thanks ..u were of great help :)
np
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