Question

reduce y=x^2+4x+3 to standard form y-b+A(x-a)^2 or x-a=A(y-b)^2

Answer 1

oh yeah and im somehow supposed to complete the square too..

Answer 2

use completing the square
subtract 3 on both sides
y-3 = x^2 +4x
Take the x coefficient, halve it ,then square it, then add to both sides
4/2 = 2 -> 2^2 = 4
y-3 +4 = x^2 +4x +4
factor, notice right side is now a perfect square
y+1 = (x+2)^2

Answer 3

This gives an upward opening parabola with vertex at (-2,-1)

Answer 4

awsum thanks!