Question

z/z^2-36 + 2/z+6

Answer 1

Well z^2-36 = (z+6)(z-6) in factored form.
So now we have:
z/(z+6)(z-6) + 2/(z+6).
The next step is to create a common denominator.
z/(z+6)(z-6) + 2(z-6)/(z+6) is created by multiplying the second term by (z-6)/(z-6).
This is your final answer.
If you want to add like terms you have:
z + 2(z-6)/(z-6)(z+6)
or
z + 3z - 12/(z-6)(z+6)
or
4z - 12/(z-6)(z+6)

All of the above are equivalent.
Hope this helps. If it does, please choose good answer.
http://www.tutorsean.net for free math videos.

Answer 2

When inputting the last answer you provided, was told it was incorrect...

Answer 3

This answer?

Answer 4

yes

Answer 5

I am unsure, because I just did all of the algebra on the equation. Are you supposed to solve for z, or just simplify the equation?

Answer 6

They are fractions to be added, I guess I don't know how to right them to look like fractions on here.

Answer 7

Neither do I, there is a technology called LaTeX that allows you to type math notation in, but I am not very good at it. So I am looking blindly at what you are trying to type, whether it be z/(z^2-36) or (z/z^2)-36. It could make a huge difference. I am very sorry that you got it incorrect. I very well could have made a math error, as I am human, but I looked it over, and also typed it into maple, and it came out fine, so I am unsure. Maybe ask a classmate or professor? There could be an error on your program?

Answer 8

I have 2 more chances at supplying a right answer, so all is well! Are you saying that I type in any of the answers u provided in fraction form and they are correct? And thoroughly simplified?

Answer 9

Let me check another source to make sure I did not make a mistake. Just a minit.

Answer 10

we are working with: z/(z^2-36) all one fraction plus 2/(z+6) all one fraction, correct?

Answer 11

Alternate forms given on wolfram alpha are as follows:
(3*(z-4))/(z^2-36)
(3*(z-4))/((z-6)*(z+6))
5/(2*(z+6)) + 1/(2*(z-6))

Hope this helps.
Sean

Answer 12

Answer they were looking for: 3z-12/(z-6)(z+6)
thanks for your work!

Answer 13

If you want to add like terms you have:
z + 2(z-6)/(z-6)(z+6)
or
[MISTAKE]
z + 3z - 12/(z-6)(z+6)
or
[MISTAKE]
4z - 12/(z-6)(z+6)
I double added in the above post. I am SO sorry about that. Please accept my sincerest apologies.
Sean
The logical steps should have been:
z+2z-12/(z-6)(z+6)

Sounds like the program is a bit on the finnicky side anyways kind of like my online spanish homework program.

Good luck!

Answer 14

Don't apologize! I'm privileged to be here asking for assistance. It's not like I'm entitled to it!!