Question

Solve and check:
1= 7/a-2 - 28/a^2-4
(fractions)
a= ??

Answer 1

yikes

Answer 2

\[1=\frac{7}{x-2}-\frac{28}{x^2-4}\] factor and add gives
\[1=\frac{7}{x-2}-\frac{28}{(x-2)(x+2)}=\frac{7(x+2)}{(x+2)(x-2)}+\frac{28}{(x-2)(x+2)}\]

Answer 3

Satellite to the rescue again!

Answer 4

\[\frac{7x+42}{(x-2)(x+2)}=1\]
\[7x+42=x^2-4\]
\[x^2-7x+46=0\]

Answer 5

a = - 2 l + 7 / l

Answer 6

Or was that a 1. Sorry,

Answer 7

no real solution damn

Answer 8

oh no i made a typo
\[x^2-7x-46=0\]

Answer 9

Damn^

Answer 10

a =5?

Answer 11

i need quadratic formula for this one. did i make an error?

Answer 12

i messed up some where. let me see where

Answer 13

bush league error i made

Answer 14

I think it's 5.

Answer 15

\[1=\frac{7}{x-2}-\frac{28}{(x-2)(x+2)}=\frac{7(x+2)}{(x+2)(x-2)}-\frac{28}{(x-2)(x+2)}\]

Answer 16

i dropped the minus sign!

Answer 17

Damn^

Answer 18

\[7x-14=x^2-4\]
\[x^2-7x+10=0\]
\[(x-2)(x-5)-0\] so
\[x=5\] because
\[x=2\] is not allowed (divide by zero and all)

Answer 19

Did you get 5 too?

Answer 20

oh lol just saw this. cool.