Find the domain of the function and express the answer in interval notation: f(x)=sqrt(4x-16)
\[4x-16\geq 0\] \[4x\geq 16\] \[x\geq4\]
because you cannot take the square root of a negative number
i would take it that the answer to this question is (-\[\infty\], 16)
\[\sqrt{4x-16}\ge 0\]
the answer is \[[4,\infty)\]
satellite is rght
the expression inside the radical must not be negative. that is why you solve \[4x-16\geq0\] for x
how would 4 be the answer, because i think i kinda figured out how to do this when its dividing.
lets go slow
this is \[f(x)=\sqrt{4x-16}\] yes?
and you have to worry about the radical, because you cannot take the square root of a negative number.
it is not the same as problems with the variable in the denominator. this time you worry about what is under the radical. it must not be negative. so we write \[4x-16\geq 0\] add 16 to get \[4x\geq16\] divide by 4 to get \[x\geq 4\]
in interval notation it is \[[4,\infty)\]
ok, i can see how you got that. i think that i just dont get how everything changes depending on how the problem is set up.
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