Question

6−2.5log(100/1)

Answer 1

\[6−2.5\log \left(\begin{matrix}100 \\ 1\end{matrix}\right)\]

Answer 2

6 - 2.5*log(100) = 6 - 2.5*2 =1

Answer 3

1

Answer 4

now it asks me for 10 times as intense

Answer 5

\[ The apparent magnitude M of a celestial body can be approximated by the formula; m=6-2.5\log(I/Io) where I is the intensity of its light, as measured from Earth, and Io is the approximate intensity of the light of the faintest stars visible \to the naked eye from Earth. Find M, if I = 0.1 and Io = 1. What is the apparent magnitude of a \star whose light is 10 \times as intense as that of the faintest \star visible \to the naked eye?\]

Answer 6

o_O